WebVisually, we can see that it is -2 std dev from the mean. We can also use the formula for z to get this: z = (x – mean)/std dev z = (74 – 82) / 4 = – 8/4 = -2 Therefore, the value 74 in our problem is the same as z = -2 Next, we do … WebSal used a simple shortcut. A z table indicates the proportion of the area of the distribution TO THE LEFT of a given z score. Given that normal distributions are by definition symmetric around their means, if we're looking for the area of just one tail in the positives, we can either subtract the proportion given by the z table from 1, or simply look at the …

If (82)p = 84, what is the value of p? 2 3 4 6 - Brainly.in

Web23 feb. 2015 · The e is standard scientific notation for powers of 10: 8.6e-28 means 8.6 ⋅ 10 − 28. The White test tests for heteroscedasticity of a variable's distribution, most commonly in the residuals of your regression. A significant result indicates that your data are significantly heteroscedastic, and thus the assumption of homoscedasticity in the ... WebTo use the calculator, simply input the z-score for the standard normal distribution, select the p-value type, and then click on the "Calculate" button to generate the results. P-Value … knight and day 2010 online subtitrat

Solve (p+2)(2p^2-5p+4) Microsoft Math Solver

Web7 jul. 2024 · target find value pf p/q^2 #1 p is a multiple of q^2 let p = 4 ; q = 1 or 2 we get different values for p/q^2 insufficient #2 q is a multiple of p. q=p*x q=4 p= 2 or 4 insufficient from 1 &2 we can say that p=4 and q=2 sucht that p/q^2 = 1 sufficient option C Web$$ P~( X 76.7 ) = P~( Z 0.67 ) $$ Step 3: Use the standard normal table to conclude that: $$ P~( Z 0.67 ) = 0.7486 $$ ... Determine the probability that a randomly selected x-value is between $15$ and $22$. example 2: ex 2: The final exam scores in a statistics class were normally distributed with a mean of $58$ and a standard deviation of $4$. Web17 nov. 2024 · If p is a positive integer, what is the value of p? 1) p/4 is a prime #. 2) p is divisible by 3. Sol: St 1 P/4 is prime so p=8,12,20,28 and so on or P is an odd multiple of 4 (Barring 8 which is an even multiple of 4 and 2 is only even prime no ). Not Sufficient St 2 p=3I where I is an integer so p=3,6,9,12 and so one red checker png