Web25 jan. 2024 · 1 Assuming that the spring is ideally following Hooke's law, i.e. F = k x the amount of the work done in displacement of the spring would be: W = ∫ F. d x = ∫ k x d x = 1 2 k x 2 1 2 k × 0.18 2 = 3 The force that holds the spring stretched at the same distance is F = 0.18 k = 2 × 3 0.18 = 100 3 Share Cite Follow answered Jan 25, 2024 at 8:09 Web15 mrt. 2024 · Attach the mass hanger s -hook and pointer to the lower end of the spring. The pointer should just touch the metre rule. Read the pointer value from the metre rule. Record this length in a suitable...

Hooke

WebHooke's Law In the diagram below is shown a block attached to a spring. In position (A) the spring is at rest and no external force acts on the block. In position (B) a force F is … Web6 nov. 2024 · We calculated that the spring constant was 62 N/m. Based on this, the potential spring energy would be. E e = 1 2 k x 2 = 1 2 ( 62.5) ( 0.187) 2 = 1.09 J. … black yellow green white red blue flag

1.2: Hooke’s Law - Physics LibreTexts

Web26 dec. 2024 · Extension happens when an object increases in length, and compression happens when it decreases in length. The extension of an elastic object, such as a … Web29 jun. 2024 · 2. In cases like Hooke's law, the rule is more important than the exceptions for downstream courses. I would only present an experimental exception after the rule … WebBy Hooke's Law, we have: F s p r i n g = k x So, to find the work needed, we have to evaluate the integral: W = ∫ a b F s p r i n g d x = ∫ a b k x d x = 1 2 k x 2 ∣ a b Since a = 0, W 4 = 18 = 1 2 k ( 4) 2 and it turns out that k = 9 4 Your value for k is 2x the correct value, which explains why your answer is 2x the correct answer. Share Cite foxy swimwear